Question

The plates of a parallel plate capacitor 5.0*10—5m apart are maintained at a potential difference of 5.0*10—4v. Calculate the magnitude of the 1) electric field intensity on the surface of the sphere. 2)force of acceleration. 3) acceleration of the electron. Note. Electron charge =1.6*10—19c, Mass electron= 9.1*10—31kg

Answer 1

1) Since we deal with the parallel plate capacitor, and the dimensions of the sphere are unknown, we need more info to answer this part.

2) The force if acceleration can be calculated as

$$F=qE=qV/d=1.6\cdot10^{—19}\cdot5\cdot10^{-4}/(5\cdot10^{-5})=\\=1.6\cdot10^{-18}\text{ N}.$$

3) According to Newton's second law, the acceleration is

$$a=F/m=1.76\cdot10^{12}\text{ m/s}^2.$$