Question #89725
(1) With a speed of 0,15m/s moves a 2,4dm long conductor perpendicular to the field lines in a field flow density is 28mT. how much voltage is induced in the conductor?
(2) a car runs at a speed of 90km / h on a horizontal wall where the earth magnetic field is 52µT and the angle of inclination is 68. how much voltage is induced between the ends of a 1.6m long axis?
(3) Two parallel metal plates are in a vacuum. the voltage between the plates is 5.7kV, according to a small plastic ball with a mass of 44mg falls at a constant speed in space between the plates. the distance between the plates is 1.7cm. calculate the ball charge
1
Expert's answer
2019-05-14T10:21:23-0400

1) If the length of the conductor is 2.4 decimeters, or 24 cm, the induced voltage will be


V=vBlsin90=0.150.240.028=0.001 V, or 1 mV.V=vBl\text{sin}90^\circ=0.15\cdot0.24\cdot0.028=0.001\text{ V, or 1 mV}.

2) Convert km/h to m/s:


u=v10003600=9010003600=25 m/s.u=v\frac{1000}{3600}=90\frac{1000}{3600}=25\text{ m/s}.

V=uBlsin68,V=uBl\text{sin}68^\circ,

V=251.6521060.93=1.93103 V, or 1.93 mV.V=25\cdot1.6\cdot52\cdot10^{-6}\cdot0.93=1.93\cdot10^{-3}\text{ V, or 1.93 mV}.

3) The magnetic field between the plates is


E=Vd.E=\frac{V}{d}.

According to Newton's second law, since the ball moves with constant speed, all forces are balanced, or mathematically:


Felectric=Fgravitational,F_\text{electric}=F_\text{gravitational},

Eq=mg,Eq=mg,

q=mgE=mgdV,q=\frac{mg}{E}=\frac{mgd}{V},

q=441069.810.0175700=1.29109 C, or 1.29 nC.q=\frac{44\cdot10^{-6}\cdot9.81\cdot0.017}{5700}=1.29\cdot10^{-9}\text{ C, or 1.29 nC}.


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