Question #87449
If the capacitor in has 0.02 m​2 plates that are 680.76 pm (pico meters) away from one another, determine what dielectric material is in between the plates if the computer was connected to a 100 Volt power supply?
1
Expert's answer
2019-04-04T08:53:10-0400

We have


S=0.02(m2);d=680.76(pm);U=100(V);E=6.5(J)S = 0.02 (m^2); d = 680.76 (pm); U = 100 (V); E=6.5 (J)

So, capacity

C=ϵϵ0SdC=\frac{\epsilon\epsilon_0 S}{d}

Energy of capacitor

E=CU22E=\frac{CU^2}{2}

To find dielectric material

ϵ=2Edϵ0SU2\epsilon=\frac{2Ed}{\epsilon_0 S U^2}

We have

ϵ=26.5680.7610128.8510120.021002=5\epsilon=\frac{2 \cdot 6.5 \cdot 680.76\cdot 10^{-12}}{8.85\cdot10^{-12}\cdot 0.02\cdot 100^2}=5

Answer: Maybe Octyl bromide or Pyrex Glass or porcelain (ceramic)


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