A resistance R and inductance L=0.01 H and a capacitance are connected in series when a voltage V=400Cos (300t-10) v is applied to the series combination, the current flowing I=10 √2cos (300t-55°)A. Find P and C.
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Expert's answer
2019-03-21T16:16:52-0400
The active power:
P=21VIcos(ϕV−ϕI)==21⋅400⋅102cos(−10∘−(−55∘))=2000 W.
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