The scheme is presented below:
and its output signal
"V_{\\text{out}}=-10V_1+0.5\\frac{dV_2}{dt}-2V_3"can be written this way:
"V_{\\text{out}}=-\\frac{R_\\text{f}}{R_1}V_1+R_\\text{f}C\\frac{dV_2}{dt}-\\frac{R_\\text{f}}{R_3}V_3,"so all you have to do is choose the resistors and capacitor satisfying these conditions:
"R_\\text{f}=10R_1=2R_3=0.5\/C"
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