I guess that the voltage is 1000=10^3 V, not 103 V.
First, find the resistance of the rod with cross-sectional area A, length L, and resistivity ρ:
R=AρL=ρL⋅πD24.
According to Ohm's law the current is
I=RV=4ρLπVD2=4⋅0.2⋅23003.14⋅103⋅0.02542=1.1⋅10−3 A,
or 1.1 mA
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