Question

What area of the plates of parallel- plate capacitor gives 1F, if the seperation of the plates is 1mm and the plates are in vacuum

Answer 1

Capacitance

$$C$$

for the capacitor with vacuum between the plates is

$$C=Aε0/d,$$

where

$$ε0=$$

8.854·10^-12 - electrical constant,

$$A$$

- area,

$$d$$

- distance between the plates.

$$A=Cd/ε0=1·0.001/ε0=112.94·10^6$$

square meters.