Question

The edges of a square pyramid are made out of wires which are conductively
connected at all vertices. Compute the resistance across the opposite vertices
on a diagonal of the base square, given that the resistance of one meter of the
wire is 1Ω, the height of the pyramid is √7 m and the base length is 2m.

Answer 1

Answer on Question #81726, Physics Electric Circuits

The edges of a square pyramid are made out of wires which are conductively connected at all vertices. Compute the resistance across the opposite vertices on a diagonal of the base square, given that the resistance of one meter of the wire is $1\Omega$ , the height of the pyramid is $\sqrt{7} \mathrm{~m}$ and the base length is $2\mathrm{~m}$ .

Solution

1/2 the diagonal of the square is: $\frac{\sqrt{8}}{2}$

Side a square pyramid: $x = \sqrt{\left(\frac{\sqrt{8}}{2}\right)^{2} + \sqrt{7}^{2}} = 3$ metres = 3 Ohm

Convert the schema:

Total resistance of this circuit $R = 1.5$ Ohm

Answer: $R = 1.5$ Ohm

Answer provided by https://www.AssignmentExpert.com