A positive 20µC charge is placed at the centre of a circle of radius 20 cm. If we
move a positive 2µC charge once along the circumference of the circle, will any
work be done in the process? Justify your answer.
1
Expert's answer
2018-02-21T04:01:07-0500
The work is
A=q(φ_1-φ_2 )
where q is the charge moving along the circumference of the circle; φ_1,φ_2 are potentials at start and finish points of moving charge, which is done by the charge placed at the centre of a circle.
φ_1=φ_2=q_1/(4πε_0 R)
where q_1 is the charge at the centre of circle, R is radius of the circle, ε_0 is the electric constant. So, A=0
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