Question

A straight conductor carrying current of 2.45 ampere floats horizontal in air in uniform magnetic field of induction 4 *10 raise to minus 4 Wb/metre square field is horizontal at right angle to length of conductor. if conductor has linear density of 0.1 g/m.Find accelaration due to gravity at that place.what is answer ?

Answer 1

Answer on Question #73055, Physics / Electric Circuits

A straight conductor carrying current of $I = 2.45$ ampere floats horizontal in air in uniform magnetic field of induction $B = 4 \times 10^{-4}$ Wb/metre square field is horizontal at right angle to length of conductor. If conductor has linear density of $\tau = 0.1 \, \text{g/m}$. Find the acceleration due to gravity at that place.

Solution:

The Newton's second law gives

$$m a = m g - F _ {\mathrm {A}}$$

where $F_{\mathrm{A}} = B Il$ is the Ampere's force.

Thus

$$a = g - \frac {F _ {\mathrm {A}}}{m} = g - \frac {B I l}{m} = g - \frac {B I}{\tau}$$ $$a = 9.8 - \frac {4 \times 10^{-4} \times 2.45}{0.0001} = 0 \, \mathrm{m/s^2}$$

Answer: $0 \, \mathrm{m/s^2}$

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