If the plates carry equal but opposite charges, the force of attraction, which is conservative, is given by
F=-∂W/∂x.
But
W=q^2/2C.
For the parallel plate capacitor,
C=(ε_0 S)/x,
where x is the distance of separation. So
F=-d/dx ((q^2 x)/(2ε_0 S))=-q^2/(2ε_0 S)=-(ε_0 SU^2)/(2d^2 ),
where we have put x=d and q=CU.
Answer. F=-(ε_0 SU^2)/(2d^2 ).
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