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Answer to Question #59042 in Electric Circuits for Emmanuel
Question #59042
The average velocity of the electrons in a piece of wire of cross-sectional area
2.0×10−6m2
2.0×10−6m2
is
2.5×10−4m/s
2.5×10−4m/s
when a steady current of 4.0 A is flowing. Calculate the number of free electrons per unit volume of the material
3×1019
3×1019
5×1020
5×1020
2×1023
2×1023
5×1028
5×1028
2.0×10−6m2
2.0×10−6m2
is
2.5×10−4m/s
2.5×10−4m/s
when a steady current of 4.0 A is flowing. Calculate the number of free electrons per unit volume of the material
3×1019
3×1019
5×1020
5×1020
2×1023
2×1023
5×1028
5×1028
Expert's answer
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