Question #58669

We are working on Ohm's law right now and I have a problem that I just can't solve. It's that there are two 10 ohm resistors in a series, which is parallel to a 100 ohm resistor and the battery. I can get all of the resistances, the batteries current, and I know that the 100 ohm resistor would be 9 volts as that's what I was given for the battery. I'm trying to get the current for all the resistors, but it doesn't add up whenever I try it. I also need to find the voltage for the two 10 ohm resistors.

Expert's answer

Answer on Question #58669 Physics - Electric Circuits


Answer

IX3=VcRX3=9100=0,09(A)I _ {X 3} = \frac {V _ {c}}{R _ {X 3}} = \frac {9}{100} = 0,09 (A)VX3=9VV _ {X 3} = 9VIX1=IX2=VcRX1=VcRX2=920=0,45(A)I _ {X 1} = I _ {X 2} = \frac {V _ {c}}{R _ {X 1}} = \frac {V _ {c}}{R _ {X 2}} = \frac {9}{20} = 0,45 (A)VX1=VX2=IX1RX1=IX2RX2=100,45=4,5(V)V _ {X 1} = V _ {X 2} = I _ {X 1} * R _ {X 1} = I _ {X 2} * R _ {X 2} = 10 * 0,45 = 4,5 (V)


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