Question #54447

n identical cells, each of emf e and internal resistance r, are joined in series to form a closed circuit. One cell A is joined with reversed polarity. The potential difference across each cell except A is? The potential difference across A is?
1

Expert's answer

2015-09-05T12:23:59-0400

Answer on Question #54447-Physics-Electric Circuits

n identical cells, each of emf e and internal resistance r, are joined in series to form a closed circuit. One cell A is joined with reversed polarity.

a. The potential difference across each cell except A is?

b. The potential difference across A is?

Solution

a.


I=ne2eNr=(n2)enrI = \frac {n e - 2 e}{N r} = \frac {(n - 2) e}{n r}V=eIr=e(n2)enrr=e(1n2n)=2en.V = e - I r = e - \frac {(n - 2) e}{n r} r = e \left(1 - \frac {n - 2}{n}\right) = \frac {2 e}{n}.


b.


V=eIr=e(n2)enrr=e(1+n2n)=2(n1)en.V = - e - I r = - e - \frac {(n - 2) e}{n r} r = - e \left(1 + \frac {n - 2}{n}\right) = - \frac {2 (n - 1) e}{n}.


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Comments

Assignment Expert
05.09.15, 19:27

Dear Misha Jain, thank you for your comment. Please, look at new answer.

Misha Jain
03.09.15, 14:58

Dear Sir/Ma'am, The pdf file of the answer you attached is of question #54438. Please provide answer of my question i.e. question #54447. Thanks & Regards

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