Question

A current of 4.8 A is flowing in a conductor. The number of electrons/second moving through any cross-section normal to direction of flow is

Answer 1

Question 36264

We are given current $I = 4.6A$ . By definition, it is the charge $Q$ which goes through cross-section normally to the direction of the flow in one second. The charge of electron is $e = 1.6\cdot 10^{-19}C$ . Hence, the number of electrons one needs to find is $N = \frac{I\cdot 1s}{e} = \frac{4.6C}{1.6\cdot 10^{-19}C} = 2.875\cdot 10^{19}$ .