Question #35917

Forces of 5.28 N and 6.50 N act at right angles on a reddish-green block of mass 8.06 kg. How much acceleration occurs?

Expert's answer

Forces of 5.28 N and 6.50 N act at right angles on a reddish-green block of mass 8.06 kg. How much acceleration occurs?

Solution

As forces of 5.28 N and 6.50 N act at right angles then the net force acting on a reddish-green block is hypotenuse of a right triangle (the legs of this triangle are forces of 5.28 N and 6.50 N).

By the Pythagorean theorem


Fnet=5.282+6.502=8.37N.F_{net} = \sqrt{5.28^2 + 6.50^2} = 8.37\,N.


By Newton's second law


Fnet=ma,F_{net} = ma,


where m – mass of block, a – its acceleration.

So


a=Fnetm=8.378.06=1.04ms2.a = \frac{F_{net}}{m} = \frac{8.37}{8.06} = 1.04\, \frac{m}{s^2}.


Answer: 1.04 ms2\frac{m}{s^2}.

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