Question #35801

the power across a 75 ohm resistor is 90w find the value of the resistance to be connected in series with 75 ohm across a supply voltage of 120 v

Expert's answer

the power across a 75 ohm resistor is 90w90\mathrm{w} and the value of the resistance to be connected in series with 75 ohm across a supply voltage of 120v120\mathrm{v}

Solution

The power across two resistors connected in series is


P=U2R1+R2=90w,P = \frac {U ^ {2}}{R _ {1} + R _ {2}} = 90\mathrm{w},


where U - a supply voltage of 120v120\mathrm{v}, R1R_{1} - a 75 ohm resistor, R2R_{2} - the value of the resistance of second resistor.

We have


R2=U2PR1=12029075=85ohm.R _ {2} = \frac {U ^ {2}}{P} - R _ {1} = \frac {120^{2}}{90} - 75 = 85\mathrm{ohm}.


Answer: 85 ohm.

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