Question #347721

An electric lamp rated 200w,240v operates for a time interval of 5 minutes calculate

(a)resistance of the lamp

(b)current flowing through the lamp

(c)electrical energy of the lamp


1
Expert's answer
2022-06-05T21:18:02-0400

Given:


U=240V;P=200W;t=5min=300s.U=240V; P=200W; t=5min=300s.

Find:

a) R-resistance of lamp;

b) I- current flowing through the lamp;

c) E-electrical energy of the lamp.

Solution:

a) P=UI=U2/R;R=P/U2;P=UI=U^2/R; R=P/U^2;

R=200W/(240V)2=0.00347Ω=3.47mΩ.R=200W/(240V)^2=0.00347\Omega=3.47 m\Omega.

b) I=P/U=200W/240V=0.833A.I=P/U=200W/240V=0.833A.

c) E=Pt=200W300s=60000J=60kJ.E=Pt=200W*300s=60000 J=60 kJ.

Answer:

a) R=3.47mΩ;R=3.47 m\Omega;

b) I=0.833A;I=0.833 A;

c) E=60kJ.E=60 kJ.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS