Question

A 240-turn solenoid is 80.0cm long and carries a current of 0.30A. Calculate the magnitude of the magnetic field at the center of solenoid.

Answer 1

Magnetic field inside solenoid is given by

$$B=\mu_0 \frac{N}{L}I$$

$$B=4\pi*10^{-7}* \frac{240}{0.80}*0.30=1.13*10^{-4}\rm T$$