Answer to Question #343940 in Electric Circuits for xavi

Question

The temperature coefficient of copper is 0.00427/°C. The resistance of the coil is 8.82 ohms

at 24°.C. Determine its resistance at 0°.C and 42°.C.

Answer 1

$R(t_2)=R(t_1)(1+\alpha (t_2-t_1))$

$R(0)=R(24)(1+\alpha (0-24))\\ =8.82*(1-0.00427*24)=7.92\:\Omega$

$R(42)=R(24)(1+\alpha (42-24))\\ =8.82*(1+0.00427*18)=9.50\:\Omega$