Question #337493

The same resistors are arranged in series 3ohms,4ohms and 11ohms.What is the total resistance of the series combination

Expert's answer

R=R1+R2+R3=3 Ω+4 Ω+11 Ω=18 ΩR=R_1+R_2+R_3\\ =3\:\Omega+4\:\Omega+11\:\Omega=18\:\Omega


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Canada #340153 on Dec 2023