why is the terminal voltage of the cell less than it's emf ?
1
Expert's answer
2013-07-18T06:46:44-0400
All sources have a non-zero effective internal resistance, that's why all sources have voltage drop on internal resistance. U = E - Ur, where U is terminal voltage, E is EMF, Ur is voltage drop on internal resistance, Ur=I*r, where r is internal resistance.
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