Question

find the potential gradient between two parallel plate conductor of separation 0.03 when potential difference of 540 supplied to them hence determine the force in an electron which club between the plates

Answer 1

The potential gradient between two parallel plate conductor

$$E=\frac{V}{d}=\frac{540\:\rm V}{0.03\:\rm m}=18000\:\rm V/m$$

The force acting on an electron

$$F=qE\\ =\rm 1.6*10^{-19}\: C\times 18000\:\rm V/m=2.88*10^{-15}\: N$$