Question #32844

An RLC circuit is used to tune a radio set to receive NOUN RADIO broadcasting at 105.9MHz in the FM band. The resistance and the inductance of the circuit of the radio set are 12Ω and 1.4μH respectively. What capacitance should the circuit have?

a. 1.64pF
b. 1.51μF
c. 1.33mF
d. 2.11pF

Expert's answer

An RLC circuit is used to tune a radio set to receive NOUN RADIO broadcasting at 105.9MHz in the FM band. The resistance and the inductance of the circuit of the radio set are 12Ω12\Omega and 1.4μH1.4\mu \mathrm{H} respectively. What capacitance should the circuit have?

a. 1.64pF

b. 1.51μF1.51\mu \mathrm{F}

c. 1.33mF

d. 2.11pF

Solution

We are given:


f=105.9MHz=105.9106Hzf = 105.9 \mathrm{MHz} = 105.9 * 10^{6} \mathrm{Hz}R=12ΩR = 12 \OmegaL=1.4μH=1.4106HL = 1.4 \mu H = 1.4 * 10^{-6} H


A radio set is tuned to receive f=105.9MHzf = 105.9 \, \text{MHz} thus resonance frequency of the RLC circuit (f0)(f_0) is equal to ff.

Resonance frequency of the RCL circuit is:


ω0=1LC\omega_0 = \sqrt{\frac{1}{LC}}f0=ω02π=1LC2πf_0 = \frac{\omega_0}{2\pi} = \frac{\sqrt{\frac{1}{LC}}}{2\pi}


So:


1LC=4π2f2\frac{1}{LC} = 4\pi^2 f^2C=14π2f2LC = \frac{1}{4\pi^2 f^2 L}C=1(4π2(105.9106)2)(1.4106)1.6131012F=1.6pFC = \frac{1}{(4\pi^2 (105.9 * 10^{6})^2) (1.4 * 10^{-6})} \approx 1.613 * 10^{-12} F = \mathbf{1.6} \, \mathbf{pF}


Closest answer is A.

Answer: A

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