Question #327335

A coil connected to a 220 V line is used to heat 500.0 g of water at 30°C. It is found out that after 5 minutes, the temperature of the water has risen to 80°C. What is the resistance of the coil? 


1
Expert's answer
2022-04-11T12:02:03-0400

The electrical energy received from the coil equals:


E=Pt=U2RtE=Pt=\frac{U^2}{R}t ,


where P - electrical power;

U - voltage;

R - resistance;

t - time.


So,


R=U2tE.R=\frac{U^2t}{E}.


Energy, required for heating of the water with mass m from the temperature T1T_1 to the temperature T2T_2 equals:


E=cm(T2T1),E=cm(T_2-T_1),


where c - specific heat capacity of the water.


So,


R=U2tcm(T2T1)=220230041840.5(8030)=138.8 Ohm.R=\frac{U^2t}{cm(T_2-T_1)}=\frac{220^2\cdot 300}{4184\cdot 0.5\cdot (80-30)}=138.8\space Ohm.


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