Question #326908

Two resistances, one 12 Ω and the other 18 Ω, are connected in parallel. What is the equivalent resistance of the parallel combination?


1
Expert's answer
2022-04-11T12:02:32-0400

The equivalent resistance of the parallel combination

R=R1R2R1+R2R=\frac{R_1R_2}{R_1+R_2}

R=121812+18=7.2ΩR=\frac{12*18}{12+18}=7.2\:\Omega


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