Eight 7.0-W Christmas tree lights are connected in series to each other and to a 110-V source. (a) Show the illustration (b) What is the resistance of each bulb?
Part (a)
(B)
Total power
P=7×8=56WP=7\times8=56WP=7×8=56W
Now current
I=56110=0.509AI=\frac{56}{110}=0.509AI=11056=0.509A
R1=PI2=70.5092=27.01ΩR_1=\frac{P}{I^2}=\frac{7}{0.509^2}=27.01\OmegaR1=I2P=0.50927=27.01Ω
Similarly
R2=PI2=70.5092=27.01ΩR_2=\frac{P}{I^2}=\frac{7}{0.509^2}=27.01\OmegaR2=I2P=0.50927=27.01Ω
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