Question #322877

21.For the network shown in Figure below, determine the current flowing in each branch.

1
Expert's answer
2022-04-04T09:05:43-0400

R1=R2=R3=1ΩR_1=R_2=R_3=1\Omega

R2,R3R_2 ,R_3

Parallel combination

R3=R2R3R2+R3=1×11+1=0.5ΩR_3=\frac{R_2R_3}{R_2+R_3}=\frac{1\times1}{1+1}=0.5\Omega

Req=0.5+1=1.5ΩR_{eq}=0.5+1=1.5\Omega

Now current calculate

I=21.5=1.33AI=\frac{2}{1.5}=1.33A

Now R2,R3R_2 ,R_3 Same current flow same


I2=I3=1.332=0.66AI_2=I_3=\frac{1.33}{2}=0.66A


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