A triangular array of resistors is shown in the figure on the right. What current will this array draw from a 35,0V battery having negligible internal resistance if we connect it across
a.) ab; b.) bc and
c.) ac?
Now R1R_1R1 And R2R_2R2 Series combination
R1′=R1+R2R_1'=R_1+R_2R1′=R1+R2
R=2RR=2RR=2R
Now
Req=2R×R2R+RR_{eq}=\frac{2R\times R}{2R+R}Req=2R+R2R×R
Req=23RR_{eq}=\frac{2}{3}RReq=32R
I=350×3R2I=\frac{350\times3R}{2}I=2350×3R
I=525AI=525AI=525A
I1′:I3=12:11I_1':I_3=\frac{1}{2}:\frac{1}{1}I1′:I3=21:11
I1′:I3=1:2I_1':I_3=1:2I1′:I3=1:2
I1′=13×525=175AI_1'=\frac{1}{3}\times525=175AI1′=31×525=175A
I3=23×525=350AI_3=\frac{2}{3}\times525=350AI3=32×525=350A
I1=I2=175AI_1=I_2=175AI1=I2=175A
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