Question #321489

An electrician experienced a mild shock when he accidentally touched a wire carrying 5.0 A for 1.5 s.



a.) How many coulombs of charge flow through the electrician?



b.) How many electrons constitute the given current?

1
Expert's answer
2022-05-28T08:23:36-0400

(a)

q=It=5.0A×1.5s=7.5  Cq=It\\=\rm 5.0\: A\times 1.5\: s=7.5\; C

(b)

N=qe=7.51.61019=4.71019N=\frac{q}{e}\\ =\frac{7.5}{1.6*10^{-19}}=4.7*10^{19}


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