Question

A steady current of 10 A maintained for 1 hr deposits 12.2 g of zinc at the

cathode. What is the equivalent mass of zinc?

Answer 1

We know that

$m=Zit$

$Z=\frac{molar mass}{nf\times F}$

$Z=\frac{65.4}{2\times96500}=3.4\times10^{-4}$

$$m=3.4\times10^{-4}\times10\times1\times60\times60=12.24g$$