A point charge q=2.00uC is located at the origin. Find the electric potential due to this charge at point x=4.0
Electric potential
V=kqrV=\frac{kq}{r}V=rkq
V=9×109×2×10−64=4.5×103VV=\frac{9\times10^9\times2\times10^{-6}}{4}=4.5\times10^{3}VV=49×109×2×10−6=4.5×103V
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