Answer to Question #319010 in Electric Circuits for Leo

Question #319010

1. Calculate the resistance of a copper wire that is 3-meter long and has a diameter of 0.005m.

2. The resistance of a piece of carbon at 200C is 10 Ω. What is its resistance at (a) 300C &(b) 100C?

providing the given, required, formula, solution/substitution of data,


1
Expert's answer
2022-03-28T11:03:11-0400
  1. Given:

l = 3 m,

d = 0.005 m,

ρ=1.7108Ohmm.\rho=1.7\cdot 10^{-8} Ohm\cdot m.

Required:

R - ?


Solution:

R=ρlS=ρ4lπd2=1.7108433.140.0052=0.0026 Ohm.R=\rho\frac{l} {S} =\rho\frac{4l} {\pi d^2}=1.7\cdot 10^{-8}\cdot \frac{4\cdot 3} {3.14\cdot 0.005^2}=0.0026\space Ohm.


2.

Given:

R0=10 Ohm,R_{0}= 10\space Ohm,

α=0.0005 1/°C,\alpha=-0.0005\space 1/\degree C,

t0=20°C,t_0=20 \degree C,

t1=30°C,t_1=30 \degree C,

t2=10°C.t_2=10 \degree C.

Required:

R1R_1 - ?

R2R_2 - ?


Solution:

R1=R0(1+α(t1t0))=10(1+(0.0005)(3020))=9.95 Ohm.R_1=R_0(1+\alpha(t_1-t_0))=10(1+(-0.0005)(30-20))=9.95\space Ohm.

R2=R0(1+α(t2t0))=10(1+(0.0005)(1020))=10.05 Ohm.R_2=R_0(1+\alpha(t_2-t_0))=10(1+(-0.0005)(10-20))=10.05\space Ohm.


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