When Asinusoidal current of maximum value of 20mA flows through aresistor ,the p.d across its ends is 400V maximum .find the energy dissipated by resistor in a time of 5minutes
The energy dissipated by resistor
"W=\\frac{I_{\\max}V_{\\max}}{2}t""W=\\frac{0.02\\:\\rm A\\times 400\\: V}{2}\\times (5\\times 60\\: \\rm s)=1200\\: J"
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