Given that C₁=10.0F, C₂=5.0F, and C3=4.0F, find the total capacitance for each connection shown.
Parrallel combination
Series combination
1Ceq=1C1+1C2+1C3\frac{1}{C_{eq}}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}Ceq1=C11+C21+C31
1Ceq=110+15+14=10+20+25100\frac{1}{C_{eq}}=\frac{1}{10}+\frac{1}{5}+\frac{1}{4}=\frac{10+20+25}{100}Ceq1=101+51+41=10010+20+25
Ceq=10055μFC_{eq}=\frac{100}{55} \mu FCeq=55100μF
Ceq=1.81μFC_{eq}=1.81\mu FCeq=1.81μF
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