Question #317569

Three resistors with values of 60.0Ω, 30.0 Ω, and 20.0 Ω, respectively, are


connected in series to a 110.0 V battery of negligible internal resistance. (a) Draw a circuit diagram and find the (b) equivalent resistance of the combined resistors, (c) current flowing through each resistor, (d) voltage drop across each resistor.


1
Expert's answer
2022-03-24T13:23:11-0400


Equivalent resistance of combined resistors is:


R = R1 + R2 + R3 = 60 + 30 + 20 = 110 Ohm.


Сurrent flowing through each resistor:


I=ER=110110=1 A.I=\frac{E}{R}=\frac{110}{110}=1\space A.


Voltage drop across each resistor:


UR1=IR1=160=60 V,UR2=IR2=130=30 V,UR3=IR3=120=20 V.U_{R1}=IR_1=1\cdot 60=60\space V,\newline U_{R2}=IR_2=1\cdot 30=30\space V,\newline U_{R3}=IR_3=1\cdot 20=20\space V.





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