Answer to Question #317569 in Electric Circuits for joee

Question

Three resistors with values of 60.0Ω, 30.0 Ω, and 20.0 Ω, respectively, are

connected in series to a 110.0 V battery of negligible internal resistance. (a) Draw a circuit diagram and find the (b) equivalent resistance of the combined resistors, (c) current flowing through each resistor, (d) voltage drop across each resistor.

Answer 1

Equivalent resistance of combined resistors is:

R = R1 + R2 + R3 = 60 + 30 + 20 = 110 Ohm.

Сurrent flowing through each resistor:

$I=\frac{E}{R}=\frac{110}{110}=1\space A.$

Voltage drop across each resistor:

$U_{R1}=IR_1=1\cdot 60=60\space V,\newline U_{R2}=IR_2=1\cdot 30=30\space V,\newline U_{R3}=IR_3=1\cdot 20=20\space V.$