Question #31746

an object is moving up an inclined plane . its velocity changes from 15 m/s to 10 m/s in two seconds.what is its acceleration?

Expert's answer

Task. An object is moving up an inclined plane. Its velocity changes from v0=15v_{0}=15 m/s to v1=10v_{1}=10 m/s in t=2t=2 seconds. What is its acceleration?

Solution. Assume that the plane moved with constant acceleration aa. Then aa can be expressed via v0v_{0}, v1v_{1} and tt by the following formula:

a=v1v0t.a=\frac{v_{1}-v_{0}}{t}.

Substituting values we get:

a=v1v0t=10152=2.5 m/s2.a=\frac{v_{1}-v_{0}}{t}=\frac{10-15}{2}=-2.5\ m/s^{2}.

The negative sign means that the velocity decreases during the motion.

Answer. a=2.5 m/s2a=2.5\ m/s^{2}.

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