Answer to Question #316480 in Electric Circuits for Azuazu Roy

Question

The current drawn from the cell when the wire is connected across A as shown is 0.3A but reduced to 0.25A, when the wire is removed leaving

A. Alone connected to the the cell determine

B. The E.M.F of the cell

C. The internal resistance of the cell

Answer 1

(1)

(B)

E=V-ir

$E=V-0.3r$

E=V-0.25r

(C)V=E-ir

r=Internal resistance