Question #316478

Three resistors with values of 60.0Ω, 30.0 Ω, and 20.0 Ω, respectively, are


connected in series to a 110.0 V battery of negligible internal resistance. (a) Draw a circuit diagram and find the (b) equivalent resistance of the combined resistors, (c) current flowing through each resistor, (d) voltage drop across each resistor.

1
Expert's answer
2022-03-24T13:23:29-0400

Explanations & Calculations


a)




b)

Req=20+30+60=110Ω\qquad\qquad \begin{aligned} \small R_{eq}&=\small 20+30+60=110\,\Omega \end{aligned}

c)

i=110.0V110Ω=1A\qquad\qquad \begin{aligned} \small i&=\small \frac{110.0\,V}{110\Omega} = 1\,A \end{aligned}

  • This current flows through each resistor as they are connected in series.


d)

V20=iR=1A×20Ω=20VV30=30VV60=60V\qquad\qquad \begin{aligned} \small V_{20}&=\small iR=1A\times20\Omega=20\,V\\ \small V_{30}&=\small 30\,V\\ \small V_{60}&=\small 60\,V \end{aligned}


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