Question

what is the force of repulsion between two(2) argon nuclei that are separated by 1x10^-9 m? The charge of one argon nucleus is +18e.

Answer 1

Force

$F=\frac{kq_1q_2}{r^2}$

$$F=\frac{9\times10^9\times18\times1.6\times10^{-19}\times18\times1.6\times10^{-19}}{(1\times10^{-9})^2}$$

$F=7.46\times10^{-8}N$