Question #31462

an eiectron beam in television tube consists of electrons accelerated from rest through a potentialdifference of about 20, 000v. what is the speed of the electron? ignore realistic effects.

Expert's answer

Question.

An electron beam in television tube consists of electrons accelerated from rest through a potential difference of about 20, 000v. What is the speed of the electron? Ignore realistic effects.

Solution

The electric field accelerates the electron beam. Acquired kinetic energy EKE_K equals work A done by field: EK=AE_K = A;

Energy and work are given by the formulas: EK=mv22;A=eUE_K = \frac{m \cdot v^2}{2}; A = e \cdot U;

Equate these values: mv22=eU\frac{mv^2}{2} = eU;

Hence we obtain: v=2eUm=21.61019200009.11031=83900(m/s)v = \sqrt{\frac{2eU}{m}} = \sqrt{\frac{2 \cdot 1.6 \cdot 10^{-19} \cdot 20000}{9.1 \cdot 10^{-31}}} = 83900 \, (m/s)

Answer: 83900 m/s.

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