Two protons in a molecule are separated by a distance of 3.6 x 10-10 m. Find the electrostatic force exerted by one proton on the other.
Explanations & Calculations
F=k.Q×Qr2=(9×109 Nm2C−2)×(+1.6×10−19 C)23.6×10−10 m=6.4×10−19 N\qquad\qquad \begin{aligned} \small F&=\small k.\frac{Q\times Q}{r^2}\\ &=\small (9\times10^9\,Nm^2C^{-2})\times\frac{(+1.6\times10^{-19}\,C)^2}{3.6\times10^{-10}\,m}\\ &=\small 6.4\times10^{-19}\,N \end{aligned}F=k.r2Q×Q=(9×109Nm2C−2)×3.6×10−10m(+1.6×10−19C)2=6.4×10−19N
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