Question #313011

An aluminum wire 5 m long and 2 mm diameter is connected in parallel with a copper wire 3m long.The total current is 4A and that is the aluminum wire is 2.5A.find the diameter of the copper wire.The resistivity of copper wire being 1.7molem and that of aluminum taken as 26nole ohms m.

1
Expert's answer
2022-03-17T09:36:01-0400

Solution.

la=5m;l_a=5m;

da=2mm=0.002m;d_a=2mm=0.002m;

ρa=2.6108Omm;\rho_a=2.6\sdot 10^{-8}Om\sdot m;

lc=3m;l_c=3m;

ρc=1.7108Omm;\rho_c=1.7\sdot10^{-8} Om\sdot m;

I=4A;I=4A;

Ia=2.5A;I_a=2.5A;

Ua=Uc    IaRa=IcRc;U_a=U_c\implies I_aR_a=I_cR_c;

Ra=ρalaSa;R_a=\rho_a\dfrac{l_a}{S_a}; Sa=πd24;S_a=\pi\dfrac{d^2}{4};

Sa=3.140.00224=3.1106m2;S_a=\dfrac{3.14\sdot0.002^2}{4}=3.1\sdot 10^{-6}m^2;

Ra=2.610853.1106=4.2102Om;R_a=2.6\sdot10^{-8}\dfrac{5}{3.1\sdot10^{-6}}=4.2\sdot 10^{-2}Om;

Rc=IaRaIc;R_c=\dfrac{I_aR_a}{I_c};

Ic=IIa=42.5=1.5A;I_c=I-I_a=4-2.5=1.5A;

Rc=2.54.21021.5=7102Om;R_c=\dfrac{2.5\sdot 4.2\sdot 10^{-2}}{1.5}=7\sdot 10^{-2}Om;

Rc=ρclcSc    Sc=ρclcRc;R_c=\rho_c\dfrac{l_c}{S_c}\implies S_c=\dfrac{\rho_cl_c}{R_c};

Sc=1.710837102=0.7106m2;S_c=\dfrac{1.7\sdot 10^{-8}\sdot3}{7\sdot 10^{-2}}=0.7\sdot 10^{-6} m^2;

Sc=πdc24    dc=2Scπ;S_c=\pi\dfrac{d_c^2}{4}\implies d_c=2\sqrt{\dfrac{S_c}{\pi}};

dc=20.71063.14=1103m=1mm;d_c=2\sqrt{\dfrac{0.7\sdot10^{-6}}{3.14}}=1\sdot 10^{-3}m=1mm;

Answer: dc=1mm.d_c=1mm.





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