Answer to Question #312979 in Electric Circuits for BxJ

Question

Three charges each 5.0x10-6C are situated at he corners of an equilateral triangle of side 1.0m. Find the force that charge q3 experienced due to the other two charges.

Answer 1

We know that

Force

$F_1=\frac{kq_3q_1}{a^2}$

$$F_1=\frac{9\times10^9\times5\times10^{-6}\times5\times10^{-6}}{1^2}=0.225N$$

$F_2=\frac{kq_2q_3}{a^2}$

$$F_2=\frac{9\times10^9\times5\times10^{-6}\times5\times10^{-6}}{1^2}=0.225N$$

$$F_{net}=\sqrt{F_1^2+F_2^2+2F_1F_2cos60°}\\F_1=F_2=F$$

We know that

$F_{net}=\sqrt{3}F$

$F_{net}=\sqrt{3}\times0.225=0.3897N$