You have five(5) 10.0 Farad capacitors. Find the total capacitance if the capacitors are connected in series.
Assume
Total capacitance
1Ct=1C1+1C2+1C3+1C4+1C5\frac{1}{C_t}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}+\frac{1}{C_4}+\frac{1}{C_5}Ct1=C11+C21+C31+C41+C51
1Ct=110+110+110+110+110\frac{1}{C_t}=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}Ct1=101+101+101+101+101
1Ct=510\frac{1}{C_t}=\frac{5}{10}Ct1=105
Cnet=2FC_{net}=2FCnet=2F
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