Question #312973

Two identical charges of 100 microcoulombs each are 12 cm apart. What is the electric potential at a point midway between them? What is the intensity of the electric field at the midway between them?

1
Expert's answer
2022-03-17T09:47:20-0400

Potential

V=V1+V2V=V_1+V_2

V=kq1r+kq2rV=\frac{kq_1}{r}+\frac{kq_2}{r}


V=9×109×100×1060.06+9×109×100×1060.06=(15+15)×106VV=\frac{9\times10^{9}\times100\times10^{-6}}{0.06}+\frac{9\times10^{9}\times100\times10^{-6}}{0.06}=(15+15)\times10^6V

V=30×106VV=30\times10^6V

Electric field

At symmetry

E=kq1r2kq2r2E=\frac{kq_1}{r^2}-\frac{kq_2}{r^2}


E=9×109×100×1060.0629×109×100×1060.062=(2525)×107V/mE=\frac{9\times10^{9}\times100\times10^{-6}}{0.06^2}-\frac{9\times10^{9}\times100\times10^{-6}}{0.06^2}=(25-25)\times10^7V/m

Enet=0V/mE_{net}=0V/m


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