What is the force between two electrons 1.0 centimeter apart in air?
constant,ke=9×109constant, k_e=9\times 10^9constant,ke=9×109
charge of electron q1=q2=1.6×10−19Cq_1=q_2=1.6\times 10^{-19}Cq1=q2=1.6×10−19C
distance, d=1cm=0.01md=1cm=0.01md=1cm=0.01m
Force, F=ke×q1q2d2=9×109×1.6×10−19×1.6×10−190.012=2.304×10−24NF=\frac{k_e \times q_1 q_2}{d^2}=\frac{9\times 10^9 \times 1.6\times 10^{-19}\times1.6 \times 10^{-19}}{0.01^2}=2.304\times 10^{-24}NF=d2ke×q1q2=0.0129×109×1.6×10−19×1.6×10−19=2.304×10−24N
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