Question #312379

What is the force between two electrons 1.0 centimeter apart in air?

1
Expert's answer
2022-03-16T18:30:09-0400

constant,ke=9×109constant, k_e=9\times 10^9

charge of electron q1=q2=1.6×1019Cq_1=q_2=1.6\times 10^{-19}C

distance, d=1cm=0.01md=1cm=0.01m

Force, F=ke×q1q2d2=9×109×1.6×1019×1.6×10190.012=2.304×1024NF=\frac{k_e \times q_1 q_2}{d^2}=\frac{9\times 10^9 \times 1.6\times 10^{-19}\times1.6 \times 10^{-19}}{0.01^2}=2.304\times 10^{-24}N


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