Answer to Question #311063 in Electric Circuits for abdi

Question

A current of 50.0A

50.0A flows through a cross-section of a wire. After six hours, what is the total mass of all of the electrons which have passed through the cross-section? Give your answer in milligrams (mg) and to three significant figures.

Answer 1

Solution.

$I=50.0A;$

$t=21600s;$

$q=It;$

$q=50.0\sdot21600=1080000C;$

$q=Ne\implies N=\dfrac{q}{e};$

$N=\dfrac{1080000}{1.6\sdot10^{-19}}=675000\sdot10^{19};$

$m=Nm_e;$

$m=675000\sdot10^{19}\sdot9.1\sdot10^{-31}=6.143\sdot10^{-6}kg=6.143mg;$

Answer: $m=6.143 mg.$