A 100 nC charge is placed at the origin. A -50 nC charge is placed at x= 5 cm and a 200 nC is placed at x= -10 cm.
a. What is the net electrostatic force acting on 100 nC charge?
Fnet=F1+F2F_{net}=F_1+F_2Fnet=F1+F2
F=kq1q2r2+kq2q3r2F=\frac{kq_1q_2}{r^2}+\frac{kq_2q_3}{r^2}F=r2kq1q2+r2kq2q3
F=kq2[200×10−9100×10−4−50×10−925×10−4]F=kq_2[\frac{200\times10^{-9}}{100\times10^{-4}}-\frac{50\times10^{-9}}{25\times10^{-4}}]F=kq2[100×10−4200×10−9−25×10−450×10−9]
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