Question

Three positively charged spheres, each with a charge of 4.0 x 10 ^-6 C, are fixed at the vertices of an equilateral triangle whose sides are 20 cm long. Calculate the magnitude of the net electrostatic force on the third charge.

a.9.24N ; Ɵ = 30°

b.16.24N ; Ɵ = -60°

c.6.24N ; Ɵ = -30°

d.8.24N ; Ɵ = -30°

Answer 1

$F=\frac{kq_1q_2}{r^2}$

$=\frac{9×10^9×(4×10^{-6})^2}{0.2^2}$

$=3.6N$

Considering the 4NC at the top Horizontal component $=0N$

Vertical component $=2×3.6\>Cos\>30$

$=6.235N$

Direction $=-30°$ from extrapolated extreme right side.